TABLE SALESPEOPLE
SNUM SNAME CITY COMM
1001 Peel London .12
1002 Serres San
Jose .13
1004 Motika London .11
1007 Rafkin Barcelona .15
1003 Axelrod New
york .1
TABLE CUST
CNUM
CNAME CITY RATING SNUM
2001 Hoffman London 100 1001
2002 Giovanne Rome 200 1003
2003 Liu San
Jose 300 1002
2004 Grass Brelin 100 1002
2006
Clemens London 300 1007
2007 Pereira Rome 100 1004
ORDERS
ONUM AMT ODATE CNUM SNUM
3001 18.69 03-OCT-94 2008 1007
3003 767.19 03-OCT-94 2001 1001
3002 1900.10
03-OCT-94 2007 1004
3005 5160.45
03-OCT-94 2003 1002
3006 1098.16
04-OCT-94 2008 1007
3009 1713.23
04-OCT-94 2002 1003
3007 75.75 05-OCT-94 2004 1002
3008 4723.00 05-OCT-94 2006 1001
3010 1309.95
06-OCT-94 2004 1002
3011 9891.88 06-OCT-94 2006 1001
1.
Which day had the hightest total amount
ordered.
Select odate, amt, snum,
cnum
from orders
where amt = (select max(amt)
from orders)
2.
Count all orders for Oct 3rd.
Select count(*)
from orders
where odate = ‘03-OCT-94’;
3.
Count the number of different non NULL city
values in customers table.
Select count(distinct city)
from cust;
4.
Select each customer’s smallest order.
Select cnum, min(amt)
from orders
group by cnum;
5.
First customer in alphabetical order whose
name begins with G.
Select min(cname)
from cust
where cname like ‘G%’;
6.
Get the output like “ For dd/mm/yy there are
___ orders.
Select 'For ' ||
to_char(odate,'dd/mm/yy') || ' there are '||
count(*) || ' Orders'
from orders
group by odate;
7.
Assume that each salesperson has a 12%
commission. Produce order no., salesperson no., and amount of salesperson’s
commission for that order.
Select onum, snum, amt, amt
* 0.12
from orders
order by snum;
8.
Find highest rating in each city. Put the
output in this form. For the city (city), the highest rating is : (rating).
Select 'For the city (' ||
city || '), the highest rating is : (' ||
max(rating) || ')'
from cust
group by city;
9.
Display the totals of orders for each day and
place the results in descending order.
Select odate, count(onum)
from orders
group by odate
order by count(onum);
10.
All
combinations of salespeople and customers who shared a city. (ie same city).
Select sname, cname
from salespeople, cust
where salespeople.city =
cust.city;
11.
Name of all
customers matched with the salespeople serving them.
Select cname, sname
from cust, salespeople
where cust.snum =
salespeople.snum;
12.
List each
order number followed by the name of the customer who made the order.
Select onum, cname
from orders, cust
where orders.cnum =
cust.cnum;
13.
Names of
salesperson and customer for each order after the order number.
Select onum, sname, cname
from orders, cust,
salespeople
where orders.cnum =
cust.cnum and
orders.snum = salespeople.snum;
14.
Produce all
customer serviced by salespeople with a commission above 12%.
Select cname, sname, comm
from cust, salespeople
where comm > 0.12 and
cust.snum = salespeople.snum;
15.
Calculate the
amount of the salesperson’s commission on each order with a rating above 100.
Select sname, amt * comm
from orders, cust,
salespeople
where rating > 100 and
salespeople.snum = cust.snum and
salespeople.snum = orders.snum and
cust.cnum = orders.cnum
16.
Find all pairs
of customers having the same rating.
Select a.cname,
b.cname,a.rating
from cust a, cust b
where a.rating = b.rating
and
a.cnum != b.cnum
17.
Find all pairs
of customers having the same rating, each pair coming once only.
Select a.cname,
b.cname,a.rating
from cust a, cust b
where a.rating = b.rating
and
a.cnum != b.cnum and
a.cnum < b.cnum;
18.
Policy is to
assign three salesperson to each customers. Display all such combinations.
Select cname, sname
from salespeople, cust
where sname in ( select sname
from salespeople
where rownum <= 3)
order by cname;
19.
Display all
customers located in cities where salesman serres has customer.
Select cname
from cust
where city = ( select city
from cust, salespeople
where cust.snum = salespeople.snum
and sname = 'Serres');
Select cname
from cust
where city in ( select city
from cust, orders
where
cust.cnum = orders.cnum and
orders.snum
in ( select snum
from salespeople
where sname = 'Serres'));
20.
Find all pairs
of customers served by single salesperson.
Select cname from cust
where snum in (select snum from cust
group by snum
having count(snum) > 1);
Select distinct a.cname
from cust a ,cust b
where a.snum = b.snum and
a.rowid != b.rowid;
21.
Produce all
pairs of salespeople which are living in the same city. Exclude combinations of
salespeople with themselves as well as duplicates with the order reversed.
Select a.sname, b.sname
from salespeople a,
salespeople b
where a.snum > b.snum and
a.city = b.city;
22.
Produce all
pairs of orders by given customer, names that customers and eliminates
duplicates.
Select c.cname, a.onum,
b.onum
from orders a, orders b,
cust c
where a.cnum = b.cnum and
a.onum > b.onum and
c.cnum = a.cnum;
23.
Produce names
and cities of all customers with the same rating as Hoffman.
Select cname, city
from cust
where rating = (select
rating
from cust
where cname = 'Hoffman')
and cname != 'Hoffman';
24.
Extract all
the orders of Motika.
Select Onum
from orders
where snum = ( select snum
from salespeople
where sname = ‘Motika’);
25.
All orders
credited to the same salesperson who services Hoffman.
Select onum, sname, cname,
amt
from orders a, salespeople
b, cust c
where a.snum = b.snum and
a.cnum = c.cnum and
a.snum = ( select snum
from orders
where
cnum = ( select cnum
from cust
where cname = 'Hoffman'));
26.
All orders
that are greater than the average for Oct 4.
Select *
from orders
where amt > ( select
avg(amt)
from orders
where odate
= '03-OCT-94');
27.
Find average
commission of salespeople in london.
Select avg(comm)
from salespeople
where city = ‘London’;
28.
Find all
orders attributed to salespeople servicing customers in london.
Select snum, cnum
from orders
where cnum in (select cnum
from cust
where city =
'London');
29.
Extract
commissions of all salespeople servicing customers in London.
Select comm
from salespeople
where snum in (select snum
from cust
where city =
‘London’);
30.
Find all customers
whose cnum is 1000 above the snum of serres.
Select cnum, cname from cust
where cnum > ( select
snum+1000
from salespeople
where sname =
'Serres');
